3.5.3 \(\int \frac {(b x+c x^2)^{5/2}}{(d+e x)^{7/2}} \, dx\) [403]

Optimal. Leaf size=392 \[ -\frac {2 \left (128 c^2 d^2-112 b c d e+15 b^2 e^2+16 c e (2 c d-b e) x\right ) \sqrt {b x+c x^2}}{15 e^5 \sqrt {d+e x}}+\frac {2 (16 c d-5 b e+6 c e x) \left (b x+c x^2\right )^{3/2}}{15 e^3 (d+e x)^{3/2}}-\frac {2 \left (b x+c x^2\right )^{5/2}}{5 e (d+e x)^{5/2}}+\frac {4 \sqrt {-b} \sqrt {c} \left (128 c^2 d^2-128 b c d e+23 b^2 e^2\right ) \sqrt {x} \sqrt {1+\frac {c x}{b}} \sqrt {d+e x} E\left (\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {x}}{\sqrt {-b}}\right )|\frac {b e}{c d}\right )}{15 e^6 \sqrt {1+\frac {e x}{d}} \sqrt {b x+c x^2}}-\frac {2 \sqrt {-b} (2 c d-b e) \left (128 c^2 d^2-128 b c d e+15 b^2 e^2\right ) \sqrt {x} \sqrt {1+\frac {c x}{b}} \sqrt {1+\frac {e x}{d}} F\left (\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {x}}{\sqrt {-b}}\right )|\frac {b e}{c d}\right )}{15 \sqrt {c} e^6 \sqrt {d+e x} \sqrt {b x+c x^2}} \]

[Out]

2/15*(6*c*e*x-5*b*e+16*c*d)*(c*x^2+b*x)^(3/2)/e^3/(e*x+d)^(3/2)-2/5*(c*x^2+b*x)^(5/2)/e/(e*x+d)^(5/2)+4/15*(23
*b^2*e^2-128*b*c*d*e+128*c^2*d^2)*EllipticE(c^(1/2)*x^(1/2)/(-b)^(1/2),(b*e/c/d)^(1/2))*(-b)^(1/2)*c^(1/2)*x^(
1/2)*(c*x/b+1)^(1/2)*(e*x+d)^(1/2)/e^6/(1+e*x/d)^(1/2)/(c*x^2+b*x)^(1/2)-2/15*(-b*e+2*c*d)*(15*b^2*e^2-128*b*c
*d*e+128*c^2*d^2)*EllipticF(c^(1/2)*x^(1/2)/(-b)^(1/2),(b*e/c/d)^(1/2))*(-b)^(1/2)*x^(1/2)*(c*x/b+1)^(1/2)*(1+
e*x/d)^(1/2)/e^6/c^(1/2)/(e*x+d)^(1/2)/(c*x^2+b*x)^(1/2)-2/15*(128*c^2*d^2-112*b*c*d*e+15*b^2*e^2+16*c*e*(-b*e
+2*c*d)*x)*(c*x^2+b*x)^(1/2)/e^5/(e*x+d)^(1/2)

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Rubi [A]
time = 0.28, antiderivative size = 392, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.348, Rules used = {746, 826, 857, 729, 113, 111, 118, 117} \begin {gather*} -\frac {2 \sqrt {-b} \sqrt {x} \sqrt {\frac {c x}{b}+1} \sqrt {\frac {e x}{d}+1} (2 c d-b e) \left (15 b^2 e^2-128 b c d e+128 c^2 d^2\right ) F\left (\text {ArcSin}\left (\frac {\sqrt {c} \sqrt {x}}{\sqrt {-b}}\right )|\frac {b e}{c d}\right )}{15 \sqrt {c} e^6 \sqrt {b x+c x^2} \sqrt {d+e x}}+\frac {4 \sqrt {-b} \sqrt {c} \sqrt {x} \sqrt {\frac {c x}{b}+1} \sqrt {d+e x} \left (23 b^2 e^2-128 b c d e+128 c^2 d^2\right ) E\left (\text {ArcSin}\left (\frac {\sqrt {c} \sqrt {x}}{\sqrt {-b}}\right )|\frac {b e}{c d}\right )}{15 e^6 \sqrt {b x+c x^2} \sqrt {\frac {e x}{d}+1}}-\frac {2 \sqrt {b x+c x^2} \left (15 b^2 e^2+16 c e x (2 c d-b e)-112 b c d e+128 c^2 d^2\right )}{15 e^5 \sqrt {d+e x}}+\frac {2 \left (b x+c x^2\right )^{3/2} (-5 b e+16 c d+6 c e x)}{15 e^3 (d+e x)^{3/2}}-\frac {2 \left (b x+c x^2\right )^{5/2}}{5 e (d+e x)^{5/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(b*x + c*x^2)^(5/2)/(d + e*x)^(7/2),x]

[Out]

(-2*(128*c^2*d^2 - 112*b*c*d*e + 15*b^2*e^2 + 16*c*e*(2*c*d - b*e)*x)*Sqrt[b*x + c*x^2])/(15*e^5*Sqrt[d + e*x]
) + (2*(16*c*d - 5*b*e + 6*c*e*x)*(b*x + c*x^2)^(3/2))/(15*e^3*(d + e*x)^(3/2)) - (2*(b*x + c*x^2)^(5/2))/(5*e
*(d + e*x)^(5/2)) + (4*Sqrt[-b]*Sqrt[c]*(128*c^2*d^2 - 128*b*c*d*e + 23*b^2*e^2)*Sqrt[x]*Sqrt[1 + (c*x)/b]*Sqr
t[d + e*x]*EllipticE[ArcSin[(Sqrt[c]*Sqrt[x])/Sqrt[-b]], (b*e)/(c*d)])/(15*e^6*Sqrt[1 + (e*x)/d]*Sqrt[b*x + c*
x^2]) - (2*Sqrt[-b]*(2*c*d - b*e)*(128*c^2*d^2 - 128*b*c*d*e + 15*b^2*e^2)*Sqrt[x]*Sqrt[1 + (c*x)/b]*Sqrt[1 +
(e*x)/d]*EllipticF[ArcSin[(Sqrt[c]*Sqrt[x])/Sqrt[-b]], (b*e)/(c*d)])/(15*Sqrt[c]*e^6*Sqrt[d + e*x]*Sqrt[b*x +
c*x^2])

Rule 111

Int[Sqrt[(e_) + (f_.)*(x_)]/(Sqrt[(b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Simp[2*(Sqrt[e]/b)*Rt[-b/
d, 2]*EllipticE[ArcSin[Sqrt[b*x]/(Sqrt[c]*Rt[-b/d, 2])], c*(f/(d*e))], x] /; FreeQ[{b, c, d, e, f}, x] && NeQ[
d*e - c*f, 0] && GtQ[c, 0] && GtQ[e, 0] &&  !LtQ[-b/d, 0]

Rule 113

Int[Sqrt[(e_) + (f_.)*(x_)]/(Sqrt[(b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Dist[Sqrt[e + f*x]*(Sqrt[
1 + d*(x/c)]/(Sqrt[c + d*x]*Sqrt[1 + f*(x/e)])), Int[Sqrt[1 + f*(x/e)]/(Sqrt[b*x]*Sqrt[1 + d*(x/c)]), x], x] /
; FreeQ[{b, c, d, e, f}, x] && NeQ[d*e - c*f, 0] &&  !(GtQ[c, 0] && GtQ[e, 0])

Rule 117

Int[1/(Sqrt[(b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol] :> Simp[(2/(b*Sqrt[e]))*Rt
[-b/d, 2]*EllipticF[ArcSin[Sqrt[b*x]/(Sqrt[c]*Rt[-b/d, 2])], c*(f/(d*e))], x] /; FreeQ[{b, c, d, e, f}, x] &&
GtQ[c, 0] && GtQ[e, 0] && (PosQ[-b/d] || NegQ[-b/f])

Rule 118

Int[1/(Sqrt[(b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol] :> Dist[Sqrt[1 + d*(x/c)]*
(Sqrt[1 + f*(x/e)]/(Sqrt[c + d*x]*Sqrt[e + f*x])), Int[1/(Sqrt[b*x]*Sqrt[1 + d*(x/c)]*Sqrt[1 + f*(x/e)]), x],
x] /; FreeQ[{b, c, d, e, f}, x] &&  !(GtQ[c, 0] && GtQ[e, 0])

Rule 729

Int[((d_.) + (e_.)*(x_))^(m_)/Sqrt[(b_.)*(x_) + (c_.)*(x_)^2], x_Symbol] :> Dist[Sqrt[x]*(Sqrt[b + c*x]/Sqrt[b
*x + c*x^2]), Int[(d + e*x)^m/(Sqrt[x]*Sqrt[b + c*x]), x], x] /; FreeQ[{b, c, d, e}, x] && NeQ[c*d - b*e, 0] &
& NeQ[2*c*d - b*e, 0] && EqQ[m^2, 1/4]

Rule 746

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(d + e*x)^(m + 1)*((
a + b*x + c*x^2)^p/(e*(m + 1))), x] - Dist[p/(e*(m + 1)), Int[(d + e*x)^(m + 1)*(b + 2*c*x)*(a + b*x + c*x^2)^
(p - 1), x], x] /; FreeQ[{a, b, c, d, e, m}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ
[2*c*d - b*e, 0] && GtQ[p, 0] && (IntegerQ[p] || LtQ[m, -1]) && NeQ[m, -1] &&  !ILtQ[m + 2*p + 1, 0] && IntQua
draticQ[a, b, c, d, e, m, p, x]

Rule 826

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Sim
p[(d + e*x)^(m + 1)*(e*f*(m + 2*p + 2) - d*g*(2*p + 1) + e*g*(m + 1)*x)*((a + b*x + c*x^2)^p/(e^2*(m + 1)*(m +
2*p + 2))), x] + Dist[p/(e^2*(m + 1)*(m + 2*p + 2)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^(p - 1)*Simp[g*(
b*d + 2*a*e + 2*a*e*m + 2*b*d*p) - f*b*e*(m + 2*p + 2) + (g*(2*c*d + b*e + b*e*m + 4*c*d*p) - 2*c*e*f*(m + 2*p
+ 2))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, m}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2
, 0] && RationalQ[p] && p > 0 && (LtQ[m, -1] || EqQ[p, 1] || (IntegerQ[p] &&  !RationalQ[m])) && NeQ[m, -1] &&
!ILtQ[m + 2*p + 1, 0] && (IntegerQ[m] || IntegerQ[p] || IntegersQ[2*m, 2*p])

Rule 857

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Dis
t[g/e, Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p, x], x] + Dist[(e*f - d*g)/e, Int[(d + e*x)^m*(a + b*x + c*x^
2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0]
&&  !IGtQ[m, 0]

Rubi steps

\begin {align*} \int \frac {\left (b x+c x^2\right )^{5/2}}{(d+e x)^{7/2}} \, dx &=-\frac {2 \left (b x+c x^2\right )^{5/2}}{5 e (d+e x)^{5/2}}+\frac {\int \frac {(b+2 c x) \left (b x+c x^2\right )^{3/2}}{(d+e x)^{5/2}} \, dx}{e}\\ &=\frac {2 (16 c d-5 b e+6 c e x) \left (b x+c x^2\right )^{3/2}}{15 e^3 (d+e x)^{3/2}}-\frac {2 \left (b x+c x^2\right )^{5/2}}{5 e (d+e x)^{5/2}}-\frac {2 \int \frac {\left (\frac {1}{2} b (16 c d-5 b e)+8 c (2 c d-b e) x\right ) \sqrt {b x+c x^2}}{(d+e x)^{3/2}} \, dx}{5 e^3}\\ &=-\frac {2 \left (128 c^2 d^2-112 b c d e+15 b^2 e^2+16 c e (2 c d-b e) x\right ) \sqrt {b x+c x^2}}{15 e^5 \sqrt {d+e x}}+\frac {2 (16 c d-5 b e+6 c e x) \left (b x+c x^2\right )^{3/2}}{15 e^3 (d+e x)^{3/2}}-\frac {2 \left (b x+c x^2\right )^{5/2}}{5 e (d+e x)^{5/2}}+\frac {4 \int \frac {\frac {1}{4} b \left (128 c^2 d^2-112 b c d e+15 b^2 e^2\right )+\frac {1}{2} c \left (128 c^2 d^2-128 b c d e+23 b^2 e^2\right ) x}{\sqrt {d+e x} \sqrt {b x+c x^2}} \, dx}{15 e^5}\\ &=-\frac {2 \left (128 c^2 d^2-112 b c d e+15 b^2 e^2+16 c e (2 c d-b e) x\right ) \sqrt {b x+c x^2}}{15 e^5 \sqrt {d+e x}}+\frac {2 (16 c d-5 b e+6 c e x) \left (b x+c x^2\right )^{3/2}}{15 e^3 (d+e x)^{3/2}}-\frac {2 \left (b x+c x^2\right )^{5/2}}{5 e (d+e x)^{5/2}}-\frac {\left ((2 c d-b e) \left (128 c^2 d^2-128 b c d e+15 b^2 e^2\right )\right ) \int \frac {1}{\sqrt {d+e x} \sqrt {b x+c x^2}} \, dx}{15 e^6}+\frac {\left (2 c \left (128 c^2 d^2-128 b c d e+23 b^2 e^2\right )\right ) \int \frac {\sqrt {d+e x}}{\sqrt {b x+c x^2}} \, dx}{15 e^6}\\ &=-\frac {2 \left (128 c^2 d^2-112 b c d e+15 b^2 e^2+16 c e (2 c d-b e) x\right ) \sqrt {b x+c x^2}}{15 e^5 \sqrt {d+e x}}+\frac {2 (16 c d-5 b e+6 c e x) \left (b x+c x^2\right )^{3/2}}{15 e^3 (d+e x)^{3/2}}-\frac {2 \left (b x+c x^2\right )^{5/2}}{5 e (d+e x)^{5/2}}-\frac {\left ((2 c d-b e) \left (128 c^2 d^2-128 b c d e+15 b^2 e^2\right ) \sqrt {x} \sqrt {b+c x}\right ) \int \frac {1}{\sqrt {x} \sqrt {b+c x} \sqrt {d+e x}} \, dx}{15 e^6 \sqrt {b x+c x^2}}+\frac {\left (2 c \left (128 c^2 d^2-128 b c d e+23 b^2 e^2\right ) \sqrt {x} \sqrt {b+c x}\right ) \int \frac {\sqrt {d+e x}}{\sqrt {x} \sqrt {b+c x}} \, dx}{15 e^6 \sqrt {b x+c x^2}}\\ &=-\frac {2 \left (128 c^2 d^2-112 b c d e+15 b^2 e^2+16 c e (2 c d-b e) x\right ) \sqrt {b x+c x^2}}{15 e^5 \sqrt {d+e x}}+\frac {2 (16 c d-5 b e+6 c e x) \left (b x+c x^2\right )^{3/2}}{15 e^3 (d+e x)^{3/2}}-\frac {2 \left (b x+c x^2\right )^{5/2}}{5 e (d+e x)^{5/2}}+\frac {\left (2 c \left (128 c^2 d^2-128 b c d e+23 b^2 e^2\right ) \sqrt {x} \sqrt {1+\frac {c x}{b}} \sqrt {d+e x}\right ) \int \frac {\sqrt {1+\frac {e x}{d}}}{\sqrt {x} \sqrt {1+\frac {c x}{b}}} \, dx}{15 e^6 \sqrt {1+\frac {e x}{d}} \sqrt {b x+c x^2}}-\frac {\left ((2 c d-b e) \left (128 c^2 d^2-128 b c d e+15 b^2 e^2\right ) \sqrt {x} \sqrt {1+\frac {c x}{b}} \sqrt {1+\frac {e x}{d}}\right ) \int \frac {1}{\sqrt {x} \sqrt {1+\frac {c x}{b}} \sqrt {1+\frac {e x}{d}}} \, dx}{15 e^6 \sqrt {d+e x} \sqrt {b x+c x^2}}\\ &=-\frac {2 \left (128 c^2 d^2-112 b c d e+15 b^2 e^2+16 c e (2 c d-b e) x\right ) \sqrt {b x+c x^2}}{15 e^5 \sqrt {d+e x}}+\frac {2 (16 c d-5 b e+6 c e x) \left (b x+c x^2\right )^{3/2}}{15 e^3 (d+e x)^{3/2}}-\frac {2 \left (b x+c x^2\right )^{5/2}}{5 e (d+e x)^{5/2}}+\frac {4 \sqrt {-b} \sqrt {c} \left (128 c^2 d^2-128 b c d e+23 b^2 e^2\right ) \sqrt {x} \sqrt {1+\frac {c x}{b}} \sqrt {d+e x} E\left (\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {x}}{\sqrt {-b}}\right )|\frac {b e}{c d}\right )}{15 e^6 \sqrt {1+\frac {e x}{d}} \sqrt {b x+c x^2}}-\frac {2 \sqrt {-b} (2 c d-b e) \left (128 c^2 d^2-128 b c d e+15 b^2 e^2\right ) \sqrt {x} \sqrt {1+\frac {c x}{b}} \sqrt {1+\frac {e x}{d}} F\left (\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {x}}{\sqrt {-b}}\right )|\frac {b e}{c d}\right )}{15 \sqrt {c} e^6 \sqrt {d+e x} \sqrt {b x+c x^2}}\\ \end {align*}

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Mathematica [C] Result contains complex when optimal does not.
time = 19.87, size = 401, normalized size = 1.02 \begin {gather*} \frac {2 (x (b+c x))^{5/2} \left (\frac {2 \left (128 c^2 d^2-128 b c d e+23 b^2 e^2\right ) (b+c x) (d+e x)}{\sqrt {x}}-\frac {e \sqrt {x} (b+c x) \left (b^2 e^2 \left (15 d^2+35 d e x+23 e^2 x^2\right )-b c e \left (112 d^3+256 d^2 e x+161 d e^2 x^2+11 e^3 x^3\right )+c^2 \left (128 d^4+288 d^3 e x+176 d^2 e^2 x^2+10 d e^3 x^3-3 e^4 x^4\right )\right )}{(d+e x)^2}+2 i \sqrt {\frac {b}{c}} c e \left (128 c^2 d^2-128 b c d e+23 b^2 e^2\right ) \sqrt {1+\frac {b}{c x}} \sqrt {1+\frac {d}{e x}} x E\left (i \sinh ^{-1}\left (\frac {\sqrt {\frac {b}{c}}}{\sqrt {x}}\right )|\frac {c d}{b e}\right )-i \sqrt {\frac {b}{c}} c e \left (128 c^2 d^2-144 b c d e+31 b^2 e^2\right ) \sqrt {1+\frac {b}{c x}} \sqrt {1+\frac {d}{e x}} x F\left (i \sinh ^{-1}\left (\frac {\sqrt {\frac {b}{c}}}{\sqrt {x}}\right )|\frac {c d}{b e}\right )\right )}{15 e^6 x^{5/2} (b+c x)^3 \sqrt {d+e x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(b*x + c*x^2)^(5/2)/(d + e*x)^(7/2),x]

[Out]

(2*(x*(b + c*x))^(5/2)*((2*(128*c^2*d^2 - 128*b*c*d*e + 23*b^2*e^2)*(b + c*x)*(d + e*x))/Sqrt[x] - (e*Sqrt[x]*
(b + c*x)*(b^2*e^2*(15*d^2 + 35*d*e*x + 23*e^2*x^2) - b*c*e*(112*d^3 + 256*d^2*e*x + 161*d*e^2*x^2 + 11*e^3*x^
3) + c^2*(128*d^4 + 288*d^3*e*x + 176*d^2*e^2*x^2 + 10*d*e^3*x^3 - 3*e^4*x^4)))/(d + e*x)^2 + (2*I)*Sqrt[b/c]*
c*e*(128*c^2*d^2 - 128*b*c*d*e + 23*b^2*e^2)*Sqrt[1 + b/(c*x)]*Sqrt[1 + d/(e*x)]*x*EllipticE[I*ArcSinh[Sqrt[b/
c]/Sqrt[x]], (c*d)/(b*e)] - I*Sqrt[b/c]*c*e*(128*c^2*d^2 - 144*b*c*d*e + 31*b^2*e^2)*Sqrt[1 + b/(c*x)]*Sqrt[1
+ d/(e*x)]*x*EllipticF[I*ArcSinh[Sqrt[b/c]/Sqrt[x]], (c*d)/(b*e)]))/(15*e^6*x^(5/2)*(b + c*x)^3*Sqrt[d + e*x])

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(2169\) vs. \(2(332)=664\).
time = 0.49, size = 2170, normalized size = 5.54

method	result	size
elliptic	\(\frac {\sqrt {x \left (c x +b \right )}\, \sqrt {x \left (e x +d \right ) \left (c x +b \right )}\, \left (-\frac {2 d^{2} \left (b^{2} e^{2}-2 b c d e +d^{2} c^{2}\right ) \sqrt {c e \,x^{3}+b e \,x^{2}+c d \,x^{2}+x b d}}{5 e^{8} \left (x +\frac {d}{e}\right )^{3}}+\frac {22 d \left (b^{2} e^{2}-3 b c d e +2 d^{2} c^{2}\right ) \sqrt {c e \,x^{3}+b e \,x^{2}+c d \,x^{2}+x b d}}{15 e^{7} \left (x +\frac {d}{e}\right )^{2}}-\frac {2 \left (c e \,x^{2}+b e x \right ) \left (23 b^{2} e^{2}-128 b c d e +128 d^{2} c^{2}\right )}{15 e^{6} \sqrt {\left (x +\frac {d}{e}\right ) \left (c e \,x^{2}+b e x \right )}}+\frac {2 c^{2} x \sqrt {c e \,x^{3}+b e \,x^{2}+c d \,x^{2}+x b d}}{5 e^{4}}+\frac {2 \left (\frac {3 c^{2} \left (b e -c d \right )}{e^{4}}-\frac {2 c^{2} \left (2 b e +2 c d \right )}{5 e^{4}}\right ) \sqrt {c e \,x^{3}+b e \,x^{2}+c d \,x^{2}+x b d}}{3 c e}+\frac {2 \left (\frac {b^{3} e^{3}-9 b^{2} d \,e^{2} c +18 b \,c^{2} d^{2} e -10 c^{3} d^{3}}{e^{6}}+\frac {11 c d \left (b^{2} e^{2}-3 b c d e +2 d^{2} c^{2}\right )}{15 e^{6}}-\frac {\left (23 b^{2} e^{2}-128 b c d e +128 d^{2} c^{2}\right ) \left (b e -c d \right )}{15 e^{6}}+\frac {b \left (23 b^{2} e^{2}-128 b c d e +128 d^{2} c^{2}\right )}{15 e^{5}}-\frac {\left (\frac {3 c^{2} \left (b e -c d \right )}{e^{4}}-\frac {2 c^{2} \left (2 b e +2 c d \right )}{5 e^{4}}\right ) b d}{3 c e}\right ) b \sqrt {\frac {\left (\frac {b}{c}+x \right ) c}{b}}\, \sqrt {\frac {x +\frac {d}{e}}{-\frac {b}{c}+\frac {d}{e}}}\, \sqrt {-\frac {c x}{b}}\, \EllipticF \left (\sqrt {\frac {\left (\frac {b}{c}+x \right ) c}{b}}, \sqrt {-\frac {b}{c \left (-\frac {b}{c}+\frac {d}{e}\right )}}\right )}{c \sqrt {c e \,x^{3}+b e \,x^{2}+c d \,x^{2}+x b d}}+\frac {2 \left (\frac {3 c \left (b^{2} e^{2}-3 b c d e +2 d^{2} c^{2}\right )}{e^{5}}+\frac {\left (23 b^{2} e^{2}-128 b c d e +128 d^{2} c^{2}\right ) c}{15 e^{5}}-\frac {3 c^{2} b d}{5 e^{4}}-\frac {2 \left (\frac {3 c^{2} \left (b e -c d \right )}{e^{4}}-\frac {2 c^{2} \left (2 b e +2 c d \right )}{5 e^{4}}\right ) \left (b e +c d \right )}{3 c e}\right ) b \sqrt {\frac {\left (\frac {b}{c}+x \right ) c}{b}}\, \sqrt {\frac {x +\frac {d}{e}}{-\frac {b}{c}+\frac {d}{e}}}\, \sqrt {-\frac {c x}{b}}\, \left (\left (-\frac {b}{c}+\frac {d}{e}\right ) \EllipticE \left (\sqrt {\frac {\left (\frac {b}{c}+x \right ) c}{b}}, \sqrt {-\frac {b}{c \left (-\frac {b}{c}+\frac {d}{e}\right )}}\right )-\frac {d \EllipticF \left (\sqrt {\frac {\left (\frac {b}{c}+x \right ) c}{b}}, \sqrt {-\frac {b}{c \left (-\frac {b}{c}+\frac {d}{e}\right )}}\right )}{e}\right )}{c \sqrt {c e \,x^{3}+b e \,x^{2}+c d \,x^{2}+x b d}}\right )}{\sqrt {e x +d}\, x \left (c x +b \right )}\)	\(912\)
default	\(\text {Expression too large to display}\)	\(2170\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2+b*x)^(5/2)/(e*x+d)^(7/2),x,method=_RETURNVERBOSE)

[Out]

-2/15*(x*(c*x+b))^(1/2)*(-768*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticF(((c*x+b)
/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^2*c^2*d^3*e^2*x+512*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)
^(1/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b*c^3*d^4*e*x-604*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e
-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^3*c*d^2*e^3*x+1024*((c*x+b)/b
)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^2*c^2
*d^3*e^2*x-512*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x+b)/b)^(1/2),(b*e/
(b*e-c*d))^(1/2))*b*c^3*d^4*e*x+92*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c
*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^4*d*e^4*x-30*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(
1/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^4*d*e^4*x+512*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d
))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^2*c^2*d^4*e+158*((c*x+b)/b)^(1/2)
*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^3*c*d^3*e^2-
384*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^
(1/2))*b^2*c^2*d^4*e-302*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x+b)/b)^(
1/2),(b*e/(b*e-c*d))^(1/2))*b^3*c*d^3*e^2+15*b^3*c*d^2*e^3*x+288*c^4*d^3*e^2*x^3+128*c^4*d^4*e*x^2+512*((c*x+b
)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^2*
c^2*d^2*e^3*x^2-256*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x+b)/b)^(1/2),
(b*e/(b*e-c*d))^(1/2))*b*c^3*d^3*e^2*x^2+316*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*Ell
ipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^3*c*d^2*e^3*x+158*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(
1/2)*(-c*x/b)^(1/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^3*c*d*e^4*x^2-384*((c*x+b)/b)^(1/2)*(
-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^2*c^2*d^2*e^3*
x^2+256*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*
d))^(1/2))*b*c^3*d^3*e^2*x^2-3*c^4*e^5*x^6-302*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*E
llipticE(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^3*c*d*e^4*x^2-15*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^
(1/2)*(-c*x/b)^(1/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^4*e^5*x^2-15*((c*x+b)/b)^(1/2)*(-(e*
x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^4*d^2*e^3-14*b*c^3
*e^5*x^5+10*c^4*d*e^4*x^5+12*b^2*c^2*e^5*x^4+176*c^4*d^2*e^3*x^4+23*b^3*c*e^5*x^3-151*b*c^3*d*e^4*x^4-126*b^2*
c^2*d*e^4*x^3-80*b*c^3*d^2*e^3*x^3+35*b^3*c*d*e^4*x^2-241*b^2*c^2*d^2*e^3*x^2+176*b*c^3*d^3*e^2*x^2-112*b^2*c^
2*d^3*e^2*x+128*b*c^3*d^4*e*x+46*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x
+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^4*e^5*x^2+256*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1
/2)*EllipticF(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b*c^3*d^5+46*((c*x+b)/b)^(1/2)*(-(e*x+d)*c/(b*e-c*d))^(
1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b^4*d^2*e^3-256*((c*x+b)/b)^(1/2)*(-(e*
x+d)*c/(b*e-c*d))^(1/2)*(-c*x/b)^(1/2)*EllipticE(((c*x+b)/b)^(1/2),(b*e/(b*e-c*d))^(1/2))*b*c^3*d^5)/(c*x+b)/x
/(e*x+d)^(5/2)/c/e^6

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x)^(5/2)/(e*x+d)^(7/2),x, algorithm="maxima")

[Out]

integrate((c*x^2 + b*x)^(5/2)/(x*e + d)^(7/2), x)

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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order 4.
time = 0.49, size = 780, normalized size = 1.99 \begin {gather*} -\frac {2 \, {\left ({\left (256 \, c^{3} d^{6} + b^{3} x^{3} e^{6} + 3 \, {\left (42 \, b^{2} c d x^{3} + b^{3} d x^{2}\right )} e^{5} - 3 \, {\left (128 \, b c^{2} d^{2} x^{3} - 126 \, b^{2} c d^{2} x^{2} - b^{3} d^{2} x\right )} e^{4} + {\left (256 \, c^{3} d^{3} x^{3} - 1152 \, b c^{2} d^{3} x^{2} + 378 \, b^{2} c d^{3} x + b^{3} d^{3}\right )} e^{3} + 6 \, {\left (128 \, c^{3} d^{4} x^{2} - 192 \, b c^{2} d^{4} x + 21 \, b^{2} c d^{4}\right )} e^{2} + 384 \, {\left (2 \, c^{3} d^{5} x - b c^{2} d^{5}\right )} e\right )} \sqrt {c} e^{\frac {1}{2}} {\rm weierstrassPInverse}\left (\frac {4 \, {\left (c^{2} d^{2} - b c d e + b^{2} e^{2}\right )} e^{\left (-2\right )}}{3 \, c^{2}}, -\frac {4 \, {\left (2 \, c^{3} d^{3} - 3 \, b c^{2} d^{2} e - 3 \, b^{2} c d e^{2} + 2 \, b^{3} e^{3}\right )} e^{\left (-3\right )}}{27 \, c^{3}}, \frac {{\left (c d + {\left (3 \, c x + b\right )} e\right )} e^{\left (-1\right )}}{3 \, c}\right ) + 6 \, {\left (128 \, c^{3} d^{5} e + 23 \, b^{2} c x^{3} e^{6} - {\left (128 \, b c^{2} d x^{3} - 69 \, b^{2} c d x^{2}\right )} e^{5} + {\left (128 \, c^{3} d^{2} x^{3} - 384 \, b c^{2} d^{2} x^{2} + 69 \, b^{2} c d^{2} x\right )} e^{4} + {\left (384 \, c^{3} d^{3} x^{2} - 384 \, b c^{2} d^{3} x + 23 \, b^{2} c d^{3}\right )} e^{3} + 128 \, {\left (3 \, c^{3} d^{4} x - b c^{2} d^{4}\right )} e^{2}\right )} \sqrt {c} e^{\frac {1}{2}} {\rm weierstrassZeta}\left (\frac {4 \, {\left (c^{2} d^{2} - b c d e + b^{2} e^{2}\right )} e^{\left (-2\right )}}{3 \, c^{2}}, -\frac {4 \, {\left (2 \, c^{3} d^{3} - 3 \, b c^{2} d^{2} e - 3 \, b^{2} c d e^{2} + 2 \, b^{3} e^{3}\right )} e^{\left (-3\right )}}{27 \, c^{3}}, {\rm weierstrassPInverse}\left (\frac {4 \, {\left (c^{2} d^{2} - b c d e + b^{2} e^{2}\right )} e^{\left (-2\right )}}{3 \, c^{2}}, -\frac {4 \, {\left (2 \, c^{3} d^{3} - 3 \, b c^{2} d^{2} e - 3 \, b^{2} c d e^{2} + 2 \, b^{3} e^{3}\right )} e^{\left (-3\right )}}{27 \, c^{3}}, \frac {{\left (c d + {\left (3 \, c x + b\right )} e\right )} e^{\left (-1\right )}}{3 \, c}\right )\right ) + 3 \, {\left (128 \, c^{3} d^{4} e^{2} - {\left (3 \, c^{3} x^{4} + 11 \, b c^{2} x^{3} - 23 \, b^{2} c x^{2}\right )} e^{6} + {\left (10 \, c^{3} d x^{3} - 161 \, b c^{2} d x^{2} + 35 \, b^{2} c d x\right )} e^{5} + {\left (176 \, c^{3} d^{2} x^{2} - 256 \, b c^{2} d^{2} x + 15 \, b^{2} c d^{2}\right )} e^{4} + 16 \, {\left (18 \, c^{3} d^{3} x - 7 \, b c^{2} d^{3}\right )} e^{3}\right )} \sqrt {c x^{2} + b x} \sqrt {x e + d}\right )}}{45 \, {\left (c x^{3} e^{10} + 3 \, c d x^{2} e^{9} + 3 \, c d^{2} x e^{8} + c d^{3} e^{7}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x)^(5/2)/(e*x+d)^(7/2),x, algorithm="fricas")

[Out]

-2/45*((256*c^3*d^6 + b^3*x^3*e^6 + 3*(42*b^2*c*d*x^3 + b^3*d*x^2)*e^5 - 3*(128*b*c^2*d^2*x^3 - 126*b^2*c*d^2*
x^2 - b^3*d^2*x)*e^4 + (256*c^3*d^3*x^3 - 1152*b*c^2*d^3*x^2 + 378*b^2*c*d^3*x + b^3*d^3)*e^3 + 6*(128*c^3*d^4
*x^2 - 192*b*c^2*d^4*x + 21*b^2*c*d^4)*e^2 + 384*(2*c^3*d^5*x - b*c^2*d^5)*e)*sqrt(c)*e^(1/2)*weierstrassPInve
rse(4/3*(c^2*d^2 - b*c*d*e + b^2*e^2)*e^(-2)/c^2, -4/27*(2*c^3*d^3 - 3*b*c^2*d^2*e - 3*b^2*c*d*e^2 + 2*b^3*e^3
)*e^(-3)/c^3, 1/3*(c*d + (3*c*x + b)*e)*e^(-1)/c) + 6*(128*c^3*d^5*e + 23*b^2*c*x^3*e^6 - (128*b*c^2*d*x^3 - 6
9*b^2*c*d*x^2)*e^5 + (128*c^3*d^2*x^3 - 384*b*c^2*d^2*x^2 + 69*b^2*c*d^2*x)*e^4 + (384*c^3*d^3*x^2 - 384*b*c^2
*d^3*x + 23*b^2*c*d^3)*e^3 + 128*(3*c^3*d^4*x - b*c^2*d^4)*e^2)*sqrt(c)*e^(1/2)*weierstrassZeta(4/3*(c^2*d^2 -
b*c*d*e + b^2*e^2)*e^(-2)/c^2, -4/27*(2*c^3*d^3 - 3*b*c^2*d^2*e - 3*b^2*c*d*e^2 + 2*b^3*e^3)*e^(-3)/c^3, weie
rstrassPInverse(4/3*(c^2*d^2 - b*c*d*e + b^2*e^2)*e^(-2)/c^2, -4/27*(2*c^3*d^3 - 3*b*c^2*d^2*e - 3*b^2*c*d*e^2
+ 2*b^3*e^3)*e^(-3)/c^3, 1/3*(c*d + (3*c*x + b)*e)*e^(-1)/c)) + 3*(128*c^3*d^4*e^2 - (3*c^3*x^4 + 11*b*c^2*x^
3 - 23*b^2*c*x^2)*e^6 + (10*c^3*d*x^3 - 161*b*c^2*d*x^2 + 35*b^2*c*d*x)*e^5 + (176*c^3*d^2*x^2 - 256*b*c^2*d^2
*x + 15*b^2*c*d^2)*e^4 + 16*(18*c^3*d^3*x - 7*b*c^2*d^3)*e^3)*sqrt(c*x^2 + b*x)*sqrt(x*e + d))/(c*x^3*e^10 + 3
*c*d*x^2*e^9 + 3*c*d^2*x*e^8 + c*d^3*e^7)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (x \left (b + c x\right )\right )^{\frac {5}{2}}}{\left (d + e x\right )^{\frac {7}{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**2+b*x)**(5/2)/(e*x+d)**(7/2),x)

[Out]

Integral((x*(b + c*x))**(5/2)/(d + e*x)**(7/2), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x)^(5/2)/(e*x+d)^(7/2),x, algorithm="giac")

[Out]

integrate((c*x^2 + b*x)^(5/2)/(x*e + d)^(7/2), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (c\,x^2+b\,x\right )}^{5/2}}{{\left (d+e\,x\right )}^{7/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x + c*x^2)^(5/2)/(d + e*x)^(7/2),x)

[Out]

int((b*x + c*x^2)^(5/2)/(d + e*x)^(7/2), x)

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